Question

How do you integrate `int_1^eln(x)/xdx`?

`int_1^eln(x)/xdx`

Answer 1

`1/2`

Explanation:

Recognise the patterns:

`int_1^eln(x)/xdx = int_1^e d((ln^2 x)/2)`

`= [(ln^2 x)/2 ]_1^e = 1/2`