How do you long divide #[(x^3)+(4x^2)-3x-12] div [(x^2)-3]#?

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Answer 1 · 2016-12-20T07:23:03

The remainder is #=0# and the quotient is #(x+4)#

Let's do the long division

#color(white)(aaaa)##x^3+4x^2-3x-12##color(white)(aaaa)##∣##x^2-3#

#color(white)(aaaa)##x^3##color(white)(aaaaaa)##-3x##color(white)(aaaaaaaaa)##∣##x+4#

#color(white)(aaaa)##0+4x^2##color(white)(aaaa)##0-12#

#color(white)(aaaaaa)##+4x^2##color(white)(aaaaaa)##-12#

#color(white)(aaaaaa)##+0##color(white)(aaaaaaaa)##-0#

The remainder is #=0# and the quotient is #(x+4)#