How do you simplify #( -14xy^4)/(18y^2) * (24x^2y^3)/(35y^2) #?

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Answer 1 · 2015-07-19T14:46:29

Factor and cancel the scalar multipliers and add/subtract exponents to find:

#(-14xy^4)/(18y^2)*(24x^2y^3)/(35y^2)=(-8x^3y^3)/15#

#(-14xy^4)/(18y^2)*(24x^2y^3)/(35y^2)#

#=((-14xy^4)(24x^2y^3))/((18y^2)(35y^2))#

#=(-2*7*3*2^3x^3y^7)/(2*3^2*5*7y^4)#

#=(-2^4*3*7x^3y^7)/(2*3^2*5*7y^4)#

#=(-2^3x^3*y^3)/(3*5)#

#=(-8x^3y^3)/15#

with exclusion #y != 0#