Question

How do you solve `2sinthetacostheta+sqrt3sintheta=0`?

Answer 1

`theta=npi` or `theta=2npi+-(5pi)/6`, where `n` is an integer

Explanation:

`2sinthetacostheta+sqrt3sintheta=0`

`hArrsintheta(2costheta+sqrt3)=0`

i.e. either `sintheta=0` and `theta=npi`, where `n` is an integer

or `2costheta+sqrt3=0` and `costheta=-sqrt3/2=cos(+-(5pi)/6)`

and `theta=2npi+-(5pi)/6`, where `n` is an integer