Question

How do you solve `3sin2x-3cosx=0` for `0<=x<=360`?

Answer 1

`3(2sinxcosx) - 3cosx= 0`

`6sinxcosx - 3cosx = 0`

`3cosx(2sinx - 1) = 0`

`cosx = 0" AND "sinx = 1/2`

`x = 90˚, 270˚, 30˚, 150˚`

Hopefully this helps!