Question

How do you solve `4-3sec^2x=0`?

Answer 1

`4-3sec^2x=0`

`=>3sec^2x=4`

`=>sec^2x=4/3`

`=>cos^2x=3/4`

`=>cosx=+-sqrt3/2`

when

`cosx=+sqrt3/2=cos (pi/6)`

then `x=2npi+-pi/6." where " n in ZZ`

when

`cosx=-sqrt3/2=cos (pi-pi/6)=cos((5pi)/6)`

then `x=2npi+-(5pi)/6." where " n in ZZ`