Question

How do you solve `4sin^2x+1=-4sinx`?

Answer 1

`x=kpi-(-1)^k(pi/6),kinZ`

Explanation:

`4sin^2x+4sinx+1=0=>(2sinx+1)^2=0` `=>2sinx+1=0=>sinx=-1/2=sin(-pi/6)`
`=>x=kpi+(-1)^k(-pi/6),kinZ`
`=>x=kpi-(-1)^k(pi/6),kinZ`