Question

How do you solve by completing the square: `x^2 + 6x + 1 = 0`?

Answer 1

x= -3+2`sqrt2`, -3-2`sqrt2`

Rewrite as `x^2` +6x+9-9+1=0
`x^2` +6x+9=8
`(x+3)^2`= 8
x+3= 2`sqrt2`, -2`sqrt2`
x= -3 + 2`sqrt2`; -3 -2`sqrt2`