Question

How do you solve `ln(lnx) = 1`?

Answer 1

I found: `x=e^e=15.154`

Explanation:

You can use the definition of logarithm:
`log_ax=b->x=a^b`
and the fact that `ln=log_e`
where `e=2.71828...`:
we can write:
`ln(ln(x))=1`
`ln(x)=e^1`
`x=e^e=15.154`