Question

How do you solve `sin(lnx)=1` in the interval [0,360]?

Answer 1

`:.x=e^(pi/2)`

Explanation:

`sin(lnx)=1`

`lnx=sin^-1 1`

`lnx=pi/2`

`e^lnx=e^(pi/2)`

`:.x=e^(pi/2)`