Question

How do you solve `sinx=-1/2`?

Answer 1

`x= (7pi)/6 ,(11pi)/6`

Explanation:

`Sin x` is negative in the `"III"^"rd"` and `"IV"^"th"` quadrants. Since

`sin pi/6=1/2`

`sin x` would be `-1/2` for `x= pi +pi/6` and for `x = 2pi -pi/6`.

The Principal solution is this

`x= (7pi)/6, (11pi)/6`