Question

How do you solve `sinx=-sqrt2/2`?

Answer 1

`x=-pi/4+2pin` or `x=-(3pi)/4 + 2pin`

Explanation:

`sinx=-sqrt2/2`

`x=sin^-1(-sqrt2/2)`

`x=-pi/4+2pin` or `x=-(3pi)/4 + 2pin`