Question

How do you solve `sinxcosx=1/2`?

Answer 1

`x= pi/4 + kpi`

Explanation:

`sin x .cos x = 1/2`
Replace in the equation (sin x.cos x) by `(sin 2x)/2` -->
`(sin 2x)/2 = 1/2`
`sin 2x = 1`
Trig unit circle -->
`2x = pi/2 + 2kpi`
`x = pi/4 + kpi`