Question

How do you solve `tanx-2-3cotx=0`?

Answer 1

In `0<=x<=2pi ;` Solution are `x=71.6^0,251.6^0,135^0,315^0`

Explanation:

`tanx-2-3cotx=0 or tanx-2-3/tanx=0 or tan^2x-2tanx-3=0 or(tanx-3)(tanx+1)=0;:.tanx-3=0 or tanx +1 =0; either tanx=3 or tanx = -1 :. x=tan^-1 (3)= 71.6^0(1dp) , (180+71.6)=251.6^0` When `tanx=-1; x=tan^-1(-1) =135^0,315^0:. 0<=x<=2pi ;` Solution are `x=71.6^0,251.6^0,135^0,315^0`[Ans]