If a rocket with a mass of 3500 tons vertically accelerates at a rate of # 3/5 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 5 seconds?

1 Answer
Sep 20, 2016

Given
#M->"Mass of rocket"=3500*10^3kg#
#a->"Acceleration"=3/5=0.6m/s^2#

#g->"Acceleration due to gravity"=9.8m/s^2#

#"Velocity after ts "(v)=at#

#"Force applied"(F)=M(g+a)#

#"Power at t s"#

#P(t)=Fxxv=M(g+a)at#

Power #"at "t=5 s#

#P(5)=35xx10^5xx(9.8+0.6)xx0.6xx5W#
#= 109.2xx10^6 W=109.2"MW"#