If a rocket with a mass of 4000 tons vertically accelerates at a rate of # 12/5 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 11 seconds?

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Answer 1 · 2017-06-22T05:49:37

The power is #=253.44MW#

We apply Newton's Second Law to find the force

#F=ma#

The mass is #m=4000*1000kg=4*10^6kg#

The acceleration is #a=12/5ms^-2#

The force is

#F=ma=4*10^6*12/5=9.6*10^6N#

We apply the equation of motion

#v=u+at#

to calculate the speed at #t=11s#

#v=0+12/5*11=26.4ms^-1#

The power is

#P=Fv#

#P=9.610^6*26.4=253.44*10^6W#

#=253.44MW#