Let #f(x)=x^2-4# and #g(x)=4x#, how do you find #(f/g)(x)#?

1 Answer
Dec 15, 2016

See explanation.

Explanation:

To find such a function you have to write an expression using the given operations with the formulas of functions #f# and #g# as arguments:

#(f/g)(x)=(x^2-4)/(4x)#

The next step is finding the domain of new function.

Both #f# and #g# are polynomials therfore are defined for all real numbers, however in #(f/g)# #g(x)# appears in the denominator. This excludes all zeros of #g(x)# from the domain. So #(f/g)# is defined for #x in RR-{0}#