Question

What are the bond angles of `PF_3Cl_2?`

Answer 1

Well, reasonably, you gots a trigonal bipyramidal geometry...

Explanation:

And so for such a `EX_5` structure there are `3xx/_X-E-X=120^@`, i.e. for the equatorial `X` ligands, and `1xx/_X-E-X=180^@`.

Of course, an `EX_5` structure, is conformationally mobile, and the axial and equatorial ligands undergo facile exchange.