Question

What are the mole fraction and the mole percent of oxygen in exhaled air if P (subscript of O2) is 116 torr and P ( subscript total) is 788 torr?

Answer 1

The mole fraction of `"O"_2"` is `0.1472`, and the mole percent is `14.72%`.

Mole fraction of oxygen gas = `(P_"O2")/(P_"total") = (116 cancel ("torr"))/(788 cancel ("torr"))=0.1472`

Mole percent of oxygen gas = `"mole fraction"xx100=0.1472xx100=14.72%`