Question

What is the base length of an equilateral triangle that has an area of approx 9.1 square centimeters?

Answer 1

`~~4.58` `cm`

Explanation:

We can see that if we split an equilateral triangle in half, we are left with two congruent equilateral triangles. Thus, one of the legs of the triangle is `1/2s`, and the hypotenuse is `s`. We can use the Pythagorean Theorem or the properties of `30˚-60˚-90˚` triangles to determine that the height of the triangle is `sqrt3/2s`.

If we want to determine the area of the entire triangle, we know that `A=1/2bh`. We also know that the base is `s` and the height is `sqrt3/2s`, so we can plug those in to the area equation to see the following for an equilateral triangle:

`A=1/2bh=>1/2(s)(sqrt3/2s)=(s^2sqrt3)/4`

We know that the area of your equilateral triangle is `9.1`.

We can set our area equation equal to `9.1`:

`9.1=(s^2sqrt3)/4`

`36.4=s^2sqrt3`

`s^2~~21.02`

`s~~4.58` `cm`