What is the derivative of #1+tan^2x#?
1 Answer
Feb 5, 2016
#2tanxsec^2x#
Explanation:
differentiate using the
#color(blue)(" chain rule ") # rewrite
# tan^2x = (tanx)^2#
#d/dx[ 1 + (tanx)^2] = 2(tanx) d/dx(tanx) #
# = 2tanxsec^2x #
