Question

What is the net area between `f(x)=ln(2/x)` in `x in[1,2]` and the x-axis?

Answer 1

`1-ln2`

Explanation:

Using the identity

`ln(a/b) -= lna-lnb`,

we can write `f(x) = ln2 - lnx`.

The area is represented by the following integral.

`int_1^2 (ln2-lnx) dx = [(ln2+1) x - xlnx]_1^2`

`= 1-ln2`