Question

Question #40e4a

Answer 1

Start by converting the 234 g of fluorine to moles.

234g / 38 g = 6.15 moles `F_2` (38 g is the molar mass of `F_2`)

No take the moles of `F_2` and convert them to moles of HF by using the mole ratio from the balanced chemical equation.

6.15 moles `F_2` x 2 moles `HF` / 1 mole `F_2` = 12.30 moles `HF`

Now use Avogadro's value 22.4 L/mole at STP to convert moles to liters.

12.30 moles `HF` x 22.4 L / 1 mole = 275.52 L `HF`

I hope this was helpful.
SMARTERTEACHER