Question #0f321

1 Answer
Ernest Z.
Mar 11, 2014

The water absorbs 7360 J.

The formula is

#q = mcΔT#

where #q# is the heat, #m# is the mass, #c# is the specific heat capacity, and #ΔT# is the temperature change.

#m = "32.0 g"#

#c = "4.184 J·K"^-1"g"^-1#

#ΔT = T_2 –T_1 = "(80.0 – 25.0) K" = "55.0 K"#

#q = mcΔT = 32.0 cancel("g") × "4.184 J"·cancel("K⁻¹g⁻¹") × 55.0 cancel("K") = "7360 J"#

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