Question #ddc52

1 Answer
Mar 7, 2014

(a) 10 L of the solution contain 2.8 kg of NaCl.
(b) 35 L of the solution contain 10 kg of NaCl.

(a) 10 L soln × #(1.18" kg soln")/(1" L soln") × (24" kg NaCl")/(100" kg soln")# = 2.8 kg NaCl

(b) 10 kg NaCl × #(100" kg soln")/(24" kg NaCl") × (1" L soln")/(1.18" kg soln")# = 35 L soln