What amount of heat is needed to raise 27.0 g of water from 10.0 °C to 90.0 °C?

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Answer 1 · 2014-06-04T01:13:19

The heat needed is 9.04 kJ.

The formula to use is

#q = mcΔT#

where #q# is the heat, #m# is the mass, #c# is the specific heat capacity, and #ΔT# is the temperature change.

#m# = 27.0 g; #c# = 4.184 J·°C⁻¹g⁻¹; #ΔT = T_2 - T_1# = (90.0 – 10.0) °C = 80.0°C

#q = mcΔT# = 27.0 g × 4.184 J·°C⁻¹g⁻¹ × 80.0 °C = 9040 J = 9.04 kJ