Question #1355e

1 Answer
Mar 26, 2014

This is a comparison of molarity by concentration and volume using the equation #n_bM_aV_a = n_aM_bV_B#.

Where
#n_b# = OH ions in the base
#M_a# = molarity of the acid
#V_a# = volume of the acid
#n_a# = H ions in the acid
#M_b# = molarity of the base
#V_b# = volume of the base

#HClO_4#
#n_a# = 1
#M_a# = ?
#V_a# = 25.00 mL

#NaOH#
#n_b# = 1
#M_b# = 0.2000M
#V_b# = 22.62 mL

#n_bM_aV_a = n_aM_bV_B#
#(1)(x M)(25.00 mL) = (1)(0.2000 M)(22.62 mL)#
#(x M)(25.00 mL) = (4.524 M mL)#
#(x M) = (4.524 M mL)/(25.00 mL)#
#(x M) = 0.1809 M#

I hope this was helpful.
SMARTERTEACHER