Question #85a0f

Question

510 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-04-27T00:57:28

To solve this problem , we will need to use the ideal gas equation;

#P_1 V_1#= nR#T_1#

#V_1# = 456 mL 0r 0.456 L

Standard Temperature is 0 degree Celsius or 273 K

#T_1# = 273 K

Standard pressure is 1 atm

#P_1# = 1 atm

#P_2# = 1.22 atm , #V_2# = ? #T_2# = 273 + 112 = 385 K

#P_1# x #V_1# / #T_1# = #P_2# x #V_2# / #T_2#

1 atm x 0.456 L / 273 K = 1.22 atm x #V_2# / 385 K

Cross multiplying

#V_2# = 1 atm x 0.456 L x 385 K / 273 K x 1.22 atm

#V_2# = 0.527 L 0r 527 mL.