Question #5a652

1 Answer
Ernest Z.
Apr 30, 2014

You use the formula #q = mcΔT#.

78.2 J = 45.6 g × #c# × 13.3 °C = #c# × 606 g°C

#c = (78.2" J")/(606" g°C")# = 0.1289 J·g⁻¹°C⁻¹

To find the molar heat capacity, you multiply by the molar mass of lead.

#c# = 0.1289 J·g⁻¹°C⁻¹ × 207.2 g·mol⁻¹ = 26.72 J·mol⁻¹°C⁻¹

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