Question

What is the domain of the function `f(x)=(x+1)/(2x-1)`?

Answer 1

With these sorts of functions the value of `x` that makes the bottom part of the fraction equal zero is a vertical asymptote .

So in this example `f(x)=(x+1)/(2x-1)`
`2x-1=0`
`2x=1`
`x=1/2`

Therefore `f(x)` is defined for every value of `x` except for `x=1/2`

Therefore the domain is `x in`[`-oo`,`1/2` )`uu` (`1/2`,`oo`]