What is the radius of convergence of the series sum_(n=0)^oo(x-4)^(2n)/3^n?

1 Answer
Sep 3, 2014

By Ratio Test, the radius of convergence is sqrt{3}.

By Ratio Test,
lim_{n to infty}|{{(x-4)^{2n+2}}/{3^{n+1}}}/{{(x-4)^{2n}}/{3^n}}| =lim_{n to infty}|{(x-4)^2}/{3}|={|x-4|^2}/3<1
by multiplying by 3,
Rightarrow |x-4|^2<3
by taking the square-root,
Rightarrow |x-4|< sqrt{3}=R

Hence, the radius of convergence is R=sqrt{3}.