How do you solve for a if $F = 7 \frac{1}{3}$ $F=7 1/3$ and $m = \frac{1}{5}$ $m=1/5$ given Newton's second law states the $a = \frac{F}{m}$ $a=F/m$ where a is the acceleration, F is the form, and m is the mass?

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Answer 1 · 2014-09-28T14:19:09

force = mass * acceleration.....(a)

f = m . a
Given ; $f = 7 + \frac{1}{3} = \frac{7 \cdot 3 + 1}{3} = \frac{22}{3}$ $f = 7 + 1/3 = (7* 3 + 1 ) / 3 = 22 /3$ unit

m = $\frac{1}{5}$ $1/5$ unit

a = $\frac{f}{m}$ $f / m$

a = $\frac{\frac{22}{3}}{\frac{1}{5}}$ $( 22 /3 ) / (1/5)$

a = $\frac{22 \cdot 5}{3 \cdot 1} = \frac{110}{3} = 36.67 or 37$ $(22 * 5)/( 3 * 1 )= 110 /3 = 36.67 or 37$ approximately.

How do you solve for a if F=713F=7 1/3 and m=15m=1/5 given Newton's second law states the a=Fma=F/m where a is the acceleration, F is the form, and m is the mass?