How do I use the quadratic formula to solve #x^2+8x=-2#?

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Answer 1 · 2014-09-30T03:26:34

#ax^2+bx+c=0#

#x^2+8x=-2#

#x^2+8x+2=0#

#a=1, b=8, c=2#

Quadratic formula

#x=(-(8)+-sqrt((8)^2-4(1)(2)))/(2(1))#

#x=(-8+-sqrt(64-8))/2#

#x=(-5+-sqrt(56))/2#

#x=(-5+-sqrt(2*2*2*7))/2#

#x=(-5+-(2)*sqrt(2*7))/2#

#x=(-5+-(2)*sqrt(14))/2#

#x=(-5+-2sqrt(14))/2#