Question

How do you evaluate the expression `(5/y)^x` when `x=2` and `y=-1`?

Answer 1

Substitute the value of x and y in the given expression;

`( 5/y)^x`

given x =2 and y =-1

`( 5/-1)^2`

`( -5) ^2`

( -5 x -5 )

25