What is the graph of #y=sin (x/3)#?

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Answer 1 · 2014-10-06T04:45:44

First, calculate the period.

#omega=(2pi)/B=(2pi)/(1/3)=((2pi)/1)*(3/1)=6pi#

Break up #6pi# into fourth by dividing by #4#.

#(6pi)/(4)=(3pi)/(2)#

#0,(3pi)/(2),3pi,(9pi)/2,6pi ->x#-values

These #x# values correspond to ...

#sin(0)=0#

#sin((pi)/(2))=1#

#sin(pi)=0#

#sin((3pi)/2)=-1#

#sin(2pi)=0#

Enter the function using the Y= button

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Press the WINDOW button.
Enter the Xmin of #0# and Xmax of #6pi#.
The calculator converts #6pi# to its decimal equivalent.

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Press the GRAPH button.

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