Question #c3e63

1 Answer
Oct 6, 2014

The empirical formula is #C_3F_6O_2#

Write down the ratio by mass C : F :O in grams:

163.8 : 518.1 : 145.4

Now work out the ratio by moles by dividing by the mass of 1 mole of each element. This is the #A_r# value in grams.

#A_r[C]=12# #A_r[F]=19# #A_r[O] = 16#

Ratio moles:

#163.8/12# : #518.1/19# :#145.4/16#

#rArr# 13.65 : 27.27 : 9.1

Divide through by 9.1 gives:

1.5 : 3 : 1

So x by 2 gives:

3 : 6 : 2

So the empirical formula is:

#C_3F_6O_2#