Question

Question #3a6f3

Answer 1

`y=8/{sinx+cosx}=8(sinx+cosx)^{-1}`

By differntiating,

`y'=-8(sinx+cosx)^{-2}(cosx-sinx)`

`={8(sinx-cosx)}/{(sinx+cosx)^2}`

In order to find an equation of a line, we will need two pieces of information:

`{("Point: "(x_1,y_1)=(0,8) Rightarrow y"-intercept: "b=8),("Slope: "m=y'(0)={8(0-1)}/{(0+1)^2}=-8):}`

By Slope-Intercept Form `y=mx+b`,

`y=-8x+8`.

I hope that this was helpful.