How do you add $3^{3} \sqrt{2} + 5^{3} \sqrt{16}$ $3""^3sqrt(2)+5""^3sqrt(16)$ ?

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How do you add $3^{3} \sqrt{2} + 5^{3} \sqrt{16}$ $3""^3sqrt(2)+5""^3sqrt(16)$ ?

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Answer 1 · 2014-10-26T02:13:38

$3 \sqrt[3]{2} + 5 \sqrt[3]{16}$ $3root(3)(2)+5root(3)(16)$ needs to be simplified in order to add.In order to add radicals, index and radicand(inside the radical) need to be the same.

Here is how you add the expression:
$3 \sqrt[3]{2} + 5 \sqrt[3]{16} =$ $3root(3)(2)+5root(3)(16)=$
$3 \sqrt[3]{2} + 5 \sqrt[3]{8 \cdot 2} =$ $3root(3)(2)+5root(3)(8*2)=$
$3 \sqrt[3]{2} + 5 (\sqrt[3]{8} \cdot \sqrt[3]{2}) =$ $3root(3)(2)+5(root(3)(8)*root(3)(2))=$
$3 \sqrt[3]{2} + 5 \cdot 2 \cdot \sqrt[3]{2} =$ $3root(3)(2)+5*2*root(3)(2)=$
$3 \sqrt[3]{2} + 10 \sqrt[3]{2} =$ $3root(3)(2)+10root(3)(2)=$
$13 \sqrt[3]{2}$ $13root(3)(2)$

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How do you add $3^{3} \sqrt{2} + 5^{3} \sqrt{16}$ $3""^3sqrt(2)+5""^3sqrt(16)$ ?

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