How do you factor 12c^2-75 completely? Algebra Polynomials and Factoring Factoring Completely 1 Answer Wataru Oct 28, 2014 12c^2-75 by factoring out 3, =3(4c^2-25) by a^2-b^2=(a+b)(a-b), =3(2c+5)(2c-5) I hope that this was helpful. Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x^2-8? Which method do you use to factor 3x(x-1)+4(x-1) ? What are the factors of 12x^3+12x^2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor x^6-26x^3-27? How do you factor 100x^2+180x+81? How do you factor x^5-5x^3-36x completely? See all questions in Factoring Completely Impact of this question 11137 views around the world You can reuse this answer Creative Commons License