Question

How do you divide `9x^2-16` by `3x+4`?

Answer 1

Treat your terms of your dividends like digits... However, you also need to consider "missing" terms (in the case of `9x^2 - 16`, the `x` term).

For your divisor, you need only divide using the first term

             3x - 4
           ____________
 (3x + 4) / (9x^2 +  0x - 16) 
          - (9x^2 + 12x)
                  - 12x - 16
               - (- 12x - 16)
                           0