Question #ba70b

1 Answer
Nov 24, 2014

Problem 1

Let #{((x_1,y_1)=(3,5)),((x_2,y_2)=(-9,5)):}#

By Slope Formula,

#m={y_2-y_1}/{x_2-x_1}={5-5}/{-9-3}=0#

By Point-Slope Form #y-y_1=m(x-x_1)#, we have the equation

#y-5=0(x-3)=0 => y=5#


Problem 2

Let #(x_1,y_1)=(2, (2)^3-10)=(2,-2)#

By rewriting the equation in Slope-Intercept Form,

#3x-2y+5=0 => y=3/2x+5/2 =># Slope #=3/2#

By taking the negative reciprocal (since perpendcular),

#m=-2/3#

By Point-Slope Form, we have the equation

#y+2=-2/3(x-2)#


Problem 3

By setting #y=0#, we can find the #x#-intercept,

#0=5x-75 => x=15 =># Let #(x_1,y_1)=(15,0)#

By rewriting in Slope-Intercept Form,

#7y-5x=70 => y=5/7x+10 => m=5/7#

By Point-Slope Form, we have the equation

#y=5/7(x-15)#


I hope that this was helpful.