What is the derivative of voltage with respect to time?

2 Answers
Dec 24, 2014

Well, when I think of derivative with respect to time I think of something changing and when voltage is involved I think of capacitors.

A capacitor is a device that can store charge #Q# when a voltage #V# is applied. This device has caracteristics (physical, geometrical) described by a constant called capacitance #C#.

The relationship between these quantities is:
#Q(t)=C*V(t)#

If you derive with respect to time you get the current through the capacitor for a varying voltage:

#d/dtQ(t)=Cd/dtV(t)#

Where the derivative of #Q(t)# is the current, i.e.:
#i(t)=Cd/dtV(t)#
This equation tells you that when the voltage doesn’t change across the capacitor, current doesn’t flow; to have current flow, the voltage must change.

(I hope it helped)

Sep 4, 2015

This only applies to Alternating Current. It is the inverse of the sin (or cos) wave form between the peak voltages.

Explanation:

Because AC voltage varies in a sinusoidal waveform, the derivative at any point is the cosine of the value.