An archer shoots an arrow with an initial velocity of 21 m/s straight up from his bow. He quickly reloads and shoots another arrow the same way 3 s later. At what time and height do the arrows meet?

1 Answer
Dec 31, 2014

The first arrow and the second meet at a height y.

Explanation:

t=3.64 s
y=11.4 m

The first arrow and the second meet at a height y.

The first one takes a time (t+3) to reach this point while the second a time t.
We use the relationship of kinematics:
y=v_it+1/2at^2
Where v_i is the initial velocity and a is the acceleration of gravity.
So we have:

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(I rounded a little bit....)