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Answer 1 · 2015-01-04T19:02:05

For capacitors in parallel:

farside.ph.utexas.edu

The total capacitance #C_(TOT# is given by:

#C_(TOT)=C_1+C_2#

Since #C_(TOT)=Q/V# the total can be found from #Q=C_(TOT)V# where V is the voltage drop across the capacitors.

For capacitors in series:

farside.ph.utexas.edu

#1/C_(TOT)=1/C_1+1/C_2#

So #Q=C_(TOT)V#