How do you derive the quadratic formula?

1 Answer
Jan 10, 2015

This is a little bit tricky but also incredibly elegant!
You start from your general quadratic:
ax^2+bx+c=0
Take c to the right side:
ax^2+bx=-c
The idea is now to transform the left side in something like (a+b)^2;
Multiply by a;
a^2x^2+abx=-ac
Multiply by 4;
4a^2x^2+4abx=-4ac
Add and subtract b^2 to the left side:
4a^2x^2+4abx+b^2-b^2=-4ac
Take the -b^2 to the right:
4a^2x^2+4abx+b^2=b^2-4ac
The left side can be written as:
(2ax+b)^2=b^2-4ac
And:
2ax+b=+-sqrt(b^2-4ac)
And finally:
x=(-b+-sqrt(b^2-4ac))/(2a)
Poetry in algebra!