Question

Question #38b86

Answer 1

The interplanar distance `d` is given by:

`d=(a)/(sqrt(h^2+k^2+l^2)`

Where `a` is the lattice parameter.

For the (1, 0, 1) case:

`d_1 = (a)/(sqrt(1^2+0+1^2))=(a)/(sqrt(2))`

For the (1, 1, 1) case:

`d_2=(a)/(sqrt(1^2+1^2+1^2))=(a)/(sqrt(3))`

So `(d_1)/(d_2)= (a)/(sqrt2)xx(sqrt3)/a`

`(d_1)/(d_2)=(sqrt3)/(sqrt2)`

So `d_1/d_2=(1.732)/(1.414)=1.22`

This shows, therefore, that `d_1>d_2`