Question

How do you evaluate `Log_2 (64)=x`?

Answer 1

You can use the definition of logarithm:
`log_a(b)=x` `->` `a^x=b`

In your case you get:

`2^x=64` which can be written as:

`2^x=2^6` (because `2^6=64`)

and finally (same base, `2` and comparing the exponents):

`x=6`