How do you simplify #4/(x+3) –6/(x-3)#?

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Answer 1 · 2015-02-04T15:07:40

The answer is: #-2(x+15)/((x+3)(x-3))#.

The least common denominator of the two denominators #x+3# and #x-3# is:

#(x+3)(x-3)#,

so:

#4/(x+3)-6/(x-3)=(4(x-3)-6(x+3))/((x+3)(x-3))=#

#=(4x-12-6x-18)/((x+3)(x-3))=(-2x-30)/((x+3)(x-3))=#

#=-2(x+15)/((x+3)(x-3))#.