Question

How do you multiply `(-2-8i)(6+7i)`?

Answer 1

You multiplly as in a normal multiplication remembering that `i=sqrt(-1)` and so `i^2=-1`;

so you get:

`(-2-8i)(6+7i)=`
`=-12-14i-48i-56i^2=`
`=-12-62i-(-1*56)=44-62i`