Prove that (a^2 - b^2 - c^2 + 2bc)/(b^2 + 2bc + c ^2 - a^2) =((s-b)(s-c))/(s(s-a)) If a + b + c = 2s?
1 Answer
Feb 21, 2015
Follow my passages:
At the numerator and at the denominator there is a difference of two squares, and remembering that:
Now, since
and simplifying for